108020433769043901318839132754528513920805844617499642188964117099518224707733815

74011445899674627353379179210735712212091688247518797177364364065078362935163284

9134 [lots of digits removed as per Mrs. Anonymous request; to see the full number, run the python code, below] 4420807

So ... can anyone tell me if it's really a prime number?

Logically, it should be; This is the code:

primes = [1]

def some_prime():

candidate = 1

for i in primes:

candidate *= i

candidate += 1

primes.append(candidate)

for i in range(1, 20): some_prime()

print primes[len(primes)-1]

Thanks :)

## 2 comments:

This looks more like an error code than a prime number :D. Anyway, i did not understand that line "candidates *=i". Shouldn't there be a check that the current candidate does not divide with any previous/2 + 1 number? This algorithm is more than i can handle at this (continuous) moment :)) But Phyton was never on my CV, so it's probably me.

Anyway, what i wanted to say is please, (re)move that prime number (wannabe) :P because it shadows the good stuff.

...and it's mrs Anonymous ;).

Done :)

The algorithm idea relies on the antique demonstration that there is an infinite number of primes.

The demonstration is a Reductio ad absurdum (I have no idea how to pronounce it in english, but in latin it sounds inteligent enough ;) ).

Basically, you postulate that the number of primes is finite, then compute the product of all the primes, and add one to the result. This will result in a new prime (doesn't divide by any of the prime numbers), so your initial postulation should be false (i.e. the total number of primes is infinite).

What I did was consider

1as the first prime, then for generating others, just compute the product of all the primes in the list, add one to the result, and add the result to the list, as a new prime.Not all primes are generated this way (5 for example is not, nor is 11), but I got to an impressive number in 20 iterations.

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